WBJEE · Physics · Semiconductors
In case of a bipolar transistor \(\beta=45\). The potential drop across the collector resistance \(\begin{array}{llllll}\text { of } 1 \mathrm{k} \Omega & \text { is } 5 \mathrm{V} . & \text { The base } & \text { current } & \text { is }\end{array}\) approximately
- A \(222 \mu \mathrm{A}\)
- B \(55 \mu \mathrm{A}\)
- C \(111 \mu \mathrm{A}\)
- D \(45 \mu \mathrm{A}\)
Answer & Solution
Correct Answer
(C) \(111 \mu \mathrm{A}\)
Step-by-step Solution
Detailed explanation
Current gain \(\beta=45\) We know that, \(\quad \beta=\frac{\Delta I_{c}}{\Delta I_{b}}\) \(\therefore\) \[ \frac{\Delta I_{c}}{\Delta I_{b}}=45 \] Potential drop across \(1 \mathrm{k} \Omega\) or \(1 \times 10^{3} \Omega\) Collector resistor is \(5 \mathrm{V}\).…
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