WBJEE · Physics · Electromagnetic Induction
The magnetic flux through a loop of resistance \(10 \Omega\) is given by \(\phi=5 t^2-4 t+1\) Weber. How much current is induced in the loop after \(0.2 \mathrm{sec}\) ?
- A \(0.4 \mathrm{~A}\)
- B \(0.2 \mathrm{~A}\)
- C \(0.04 \mathrm{~A}\)
- D \(0.02 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(0.2 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Hints : \(\phi=5 t^2-4 t+1\) \[ \frac{d \phi}{d t}=10 t-4 \] \[ \mathrm{I}=\frac{e}{\mathrm{R}}=\frac{-d \phi / d t}{\mathrm{R}}=-\frac{10 t-4}{10} \] At \(t=0.2 \mathrm{sec}\)…
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