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WBJEE · Physics · Electromagnetic Induction

The magnetic flux through a loop of resistance \(10 \Omega\) is given by \(\phi=5 t^2-4 t+1\) Weber. How much current is induced in the loop after \(0.2 \mathrm{sec}\) ?

  1. A \(0.4 \mathrm{~A}\)
  2. B \(0.2 \mathrm{~A}\)
  3. C \(0.04 \mathrm{~A}\)
  4. D \(0.02 \mathrm{~A}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.2 \mathrm{~A}\)

Step-by-step Solution

Detailed explanation

Hints : \(\phi=5 t^2-4 t+1\) \[ \frac{d \phi}{d t}=10 t-4 \] \[ \mathrm{I}=\frac{e}{\mathrm{R}}=\frac{-d \phi / d t}{\mathrm{R}}=-\frac{10 t-4}{10} \] At \(t=0.2 \mathrm{sec}\)…
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