WBJEE · Physics · Electrostatics
The number of electron in 2 coulomb of charge is
- A \(5 \times 10^{29}\)
- B \(12.5 \times 10^{18}\)
- C \(1.6 \times 10^{19}\)
- D \(9 \times 10^{11}\)
Answer & Solution
Correct Answer
(B) \(12.5 \times 10^{18}\)
Step-by-step Solution
Detailed explanation
\(n=\frac{2}{1.6 \times 10^{-19}}=12.5 \times 10^{18}\)
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