WBJEE · Physics · Electrostatics
A hollow metal sphere of radius \(R\) is charged with a charge \(Q .\) The electric potential and intensity inside the sphere are respectively
- A \(\frac{Q}{4 \pi \varepsilon_{0} R^{2}}\) and \(\frac{Q}{4 \pi \varepsilon_{0} R}\)
- B \(\frac{Q}{4 \pi \varepsilon_{0} R}\) and zero
- C zero and zero
- D \(\frac{4 \pi \varepsilon_{0} Q}{R}\) and \(\frac{Q}{4 \pi \varepsilon_{0} R^{2}}\)
Answer & Solution
Correct Answer
(B) \(\frac{Q}{4 \pi \varepsilon_{0} R}\) and zero
Step-by-step Solution
Detailed explanation
Inside a hollow charged sphere, the electric field intensity is always zero. \(\therefore\) \(E=0\) but potential is constant. Potential on the surtace of the hollow sphere \[ V=\frac{K Q}{R}=\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{Q}{R}=\frac{Q}{4 \pi \varepsilon_{0} R} \]…
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