WBJEE · Physics · Electrostatics
Four charges equal to \(-Q\) are placed at the four corners of a square and a charge \(q\) is at its centre. If the system is in equilibrium, the value of \(q\) is
- A \(\frac{-Q}{4}(1+2 \sqrt{2})\)
- B \(\frac{Q}{4}(1+2 \sqrt{2})\)
- C \(\frac{-\mathrm{Q}}{2}(1+2 \sqrt{2})\)
- D \(\frac{\mathrm{Q}}{2}(1+2 \sqrt{2})\)
Answer & Solution
Correct Answer
(B) \(\frac{Q}{4}(1+2 \sqrt{2})\)
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