WBJEE · Physics · Motion In One Dimension
The acceleration ' \(a\) ' (in \(\mathrm{ms}^{-2}\) ) of a body, starting from rest varies with time \(t\) (in \(s\) ) following the equation \(a=3 t+4\) The velocity of the body at time \(t=2 \mathrm{~s}\) will be
- A \(10 \mathrm{~ms}^{-1}\)
- B \(18 \mathrm{~ms}^{-1}\)
- C \(14 \mathrm{~ms}^{-1}\)
- D \(26 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(14 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
\(a=3 t+4\) \(\begin{aligned} & \frac{d V}{d t}=3 t+4 \\ & \int_0^V d V=\int_0^t(3 t+4) d t \\ & V=\frac{3 t^2}{2}+4 t=\frac{12}{2}+8=14 \mathrm{~m} / \mathrm{s}\end{aligned}\)
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