WBJEE · Physics · Center of Mass Momentum and Collision
The variation of density of a solid cylindrical rod of cross sectional area \(\alpha\) and length \(L\) is \(\rho=\rho_0 \frac{x^2}{L^2}\), where x is the distance from one end of the rod. The position of its centre of mass from one end \((x=0)\) is
- A 2L/3
- B L/2
- C L/3
- D 3L/4
Answer & Solution
Correct Answer
(D) 3L/4
Step-by-step Solution
Detailed explanation
\(\rho=\rho_0 \frac{x^2}{L^2}\),…
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