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WBJEE · Maths · Definite Integration

The value of the integral \(\int_{-2}^{2}(1+2 \sin x) e^{|x|} d x\) is
equal to

  1. A 0
  2. B \(e^{2}-1\)
  3. C \(2\left(e^{2}-1\right)\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(C) \(2\left(e^{2}-1\right)\)

Step-by-step Solution

Detailed explanation

\(\int_{-2}^{2}(1+2 \sin x) e^{|x|} d x\) \(=\int_{-2}^{2} e^{|x|} d x+2 \int_{-2}^{2} \sin x e^{|x|} d x\) (Since, first function is even and second function is odd). \(=2 \int_{0}^{2} e^{|x|} d x+2 \text{ instead of ,} 0=2\left[e^{|x|}\right]_{0}^{2}=2\left(e^{2}-1\right)\)