WBJEE · Maths · Definite Integration
The value of the integral \(\int_{-2}^{2}(1+2 \sin x) e^{|x|} d x\) is
equal to
- A 0
- B \(e^{2}-1\)
- C \(2\left(e^{2}-1\right)\)
- D 1
Answer & Solution
Correct Answer
(C) \(2\left(e^{2}-1\right)\)
Step-by-step Solution
Detailed explanation
\(\int_{-2}^{2}(1+2 \sin x) e^{|x|} d x\) \(=\int_{-2}^{2} e^{|x|} d x+2 \int_{-2}^{2} \sin x e^{|x|} d x\) (Since, first function is even and second function is odd). \(=2 \int_{0}^{2} e^{|x|} d x+2 \text{ instead of ,} 0=2\left[e^{|x|}\right]_{0}^{2}=2\left(e^{2}-1\right)\)
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