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WBJEE · Chemistry · Surface Chemistry

The amount of electrolytes required to coagulate a given amount of Agl colloidal solution (-ve charge) will be in the order

  1. A \(NaNO_{3}>\mathrm{Al}_{2}\left(\mathrm{NO}_{3}\right)_{3}>\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\)
  2. B \(\mathrm{Al}_{2}\left(\mathrm{NO}_{3}\right)_{3}>\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}>\mathrm{NaNO}_{3}\)
  3. C \(\mathrm{Al}_{2}\left(\mathrm{NO}_{3}\right)_{3}>\mathrm{NaNO}_{3}>\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\)
  4. D \(\mathrm{NaNO}_{3}>\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}>\mathrm{Al}_{2}\left(\mathrm{NO}_{3}\right)_{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{NaNO}_{3}>\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}>\mathrm{Al}_{2}\left(\mathrm{NO}_{3}\right)_{3}\)

Step-by-step Solution

Detailed explanation

Since, AgI is a negatively charged sol, so according to Hardy Schulze law, higher the positive charge on the metal atoms, more is the tendency of metal atom to cause coagulation of negatively charged colloid. The order of positive charge is…