WBJEE · Chemistry · Electrochemistry
Given the standard half-cell potentials \(\left(E^{\circ}\right)\) of
the following as
\[
\begin{array}{l}
\text { Zn } \longrightarrow \mathrm{Zn}^{2+}+2 e^{-} ; \quad E^{\circ}=+0.76 \mathrm{V} \\
\mathrm{Fe} \longrightarrow \mathrm{Fe}^{2+}+2 e^{-} ; \quad E^{\circ}=0.41 \mathrm{V}
\end{array}
\]
Then the standard e.m.f. of the cell with the reaction \(\mathrm{Fe}^{2+}+\mathrm{Zn} \longrightarrow \mathrm{Zn}^{2+}+\mathrm{Fe}\) is
- A \(-0.35 V\)
- B \(+0.35 \vee\)
- C \(+117 V\)
- D \(-117 \mathrm{V}\)
Answer & Solution
Correct Answer
(B) \(+0.35 \vee\)
Step-by-step Solution
Detailed explanation
Given, \(\mathrm{Zn} \longrightarrow \mathrm{Zn}^{2+}+2 \mathrm{e}^{-} ; E^{\circ}=+0.76 \mathrm{V}\) \[ \mathrm{Fe} \longrightarrow \mathrm{Fe}^{2+}+2 e^{-} ; E^{\circ}=+0.41 \mathrm{V} \] On reversing the above equation (i) and (ii), we get…
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