WBJEE · Maths · Definite Integration
Let \(f(x)\) be a continuous periodic function with period \(T\). Let \(I=\int_{a}^{a+T} f(x) d x\). Then
- A \(\mathrm{I}\) is linear function in ' \(\mathrm{a}\) '
- B I does not depend on ' \(a\) '
- C \(0 < \mathrm{I} < \mathrm{a}^{2}+1\) where \(\mathrm{I}\) depends on ' \(\mathrm{a}\) '
- D \(\mathrm{I}\) is quadratic function in ' \(\mathrm{a}\) '
Answer & Solution
Correct Answer
(B) I does not depend on ' \(a\) '
Step-by-step Solution
Detailed explanation
\(I=\int_{a}^{a+T} f(x) d x=\int_{0}^{T} f(x) d x\) I does not depend on a.
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