WBJEE · Maths · Binomial Theorem
Using binomial theorem, the value of \((0.999)^3\) correct to 3 decimal places is
- A 0.999
- B 0.998
- C 0.997
- D 0.995
Answer & Solution
Correct Answer
(C) 0.997
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Hints : }{ }^3 C_0-{ }^3 C_1(.001)+{ }^3 C_2(.001)^2-{ }^3 C_3(.001)^3 \\ & =1-.003+3(.000001)-(.000000001)=0.997 \end{aligned} \]
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