WBJEE · Physics · Nuclear Physics
What is the particle \(\mathrm{x}\) in the following nuclear reaction :
\({ }_4^9 \mathrm{Be}+{ }_2^4 \mathrm{He} \rightarrow{ }_6^{12} \mathrm{C}+\mathrm{x}\)
- A electron
- B proton
- C Photon
- D Neutron
Answer & Solution
Correct Answer
(D) Neutron
Step-by-step Solution
Detailed explanation
\({ }_4^9 \mathrm{Be}+{ }_2^4 \mathrm{He} \rightarrow{ }_6^{12} \mathrm{C}+{ }_0^1 \mathrm{X}\) Hence X represents neutron \(\left({ }_0^1 n\right)\)
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