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WBJEE · Maths · Definite Integration

The value of
\(I=\int_{\pi / 2}^{5 \pi / 2} \frac{e^{\tan ^{-1}}(\sin x)}{e^{\tan ^{-1}(\sin x)}+e^{\tan ^{-1}(\cos x)}} d x,\) is

  1. A 1
  2. B \(\pi\)
  3. C e
  4. D \(\frac{\pi}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\pi\)

Step-by-step Solution

Detailed explanation

Let \(I=\int_{\pi / 2}^{5 \pi / 2} \frac{e^{\tan ^{-1}}(\sin x)}{e^{\tan ^{-1}(\sin x)}+e^{\tan ^{-1}(\cos x)}} d x\) \(=\int_{0}^{5 \pi / 2} \frac{e^{\tan ^{-1}(\sin x)}}{e^{\tan ^{-1}(\sin x)}+e^{\tan ^{-1}(\cos x)}} d x\)…