WBJEE · Maths · Circle
If the circle \(x^{2}+y^{2}+2 g x+2 f y+c=0\) cuts the three circles \(x^{2}+y^{2}-5=0\) \(x^{2}+y^{2}-8 x-6 y+10=0\) and \(x^{2}+y^{2}-4 x+2 y-2=0\) at the extremities of their diameters, then
- A \(c=-5\)
- B \(f g=147 / 25\)
- C \(g+2 t=c+2\)
- D \(4 f=3 g\)
Answer & Solution
Correct Answer
(D) \(4 f=3 g\)
Step-by-step Solution
Detailed explanation
Centres and constant terms in the circles \(x^{2}+y^{2}-5=0, x^{2}+y^{2}-8 x-6 y+10=0\) and \(x^{2}+y^{2}-4 x+2 y-2=0\) are \(C_{1}^{\prime}(0,0), c_{1}=-5\) \(C_{2}^{\prime}(4,3), c_{2}=10\) and \(C_{3}^{\prime}(2,-1), c_{3}=-2\) Also, centre and constant of circle…
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