WBJEE · Maths · Functions
Two particles \(A\) and \(B\) move from rest along a straight line with constant accelerations \(f\) and \(h,\) respectively. If \(A\) takes \(m\) seconds more than \(B\) and describes \(n\) units more than that of \(B\) acquiring the same speed, then
- A \((f+h) m^{2}=h n\)
- B \((f-f h) m^{2}=f h n\)
- C \((h-f) n=\frac{1}{2}\) \(fhm^{2}\)
- D \(\frac{1}{2}(f+h) n=\) \(fhm^{2}\)
Answer & Solution
Correct Answer
(C) \((h-f) n=\frac{1}{2}\) \(fhm^{2}\)
Step-by-step Solution
Detailed explanation
Let \(B\) travels \(x\) units, \(v=u+a t\) According to problem, \(h t=f(t+m)\) \(\begin{aligned} h t=& f t+f m \\ h t-f t &=f m \\ t(h-f) &=f m \\ \frac{h-f}{f} &=\frac{m}{t} \end{aligned}\) \(t=m\left(\frac{f}{h-f}\right)\)…
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