TS EAMCET · Physics · Mechanical Properties of Solids
When a force \(F_1\) is applied on a metallic wire, the length of the wire is \(L_1\). If a force \(F_2\) is applied on the same wire, the length of the wire is \(L_2\). The original length of the wire \(L\) is
- A \(\frac{L_1 F_1+L_2 F_2}{F_1+F_2}\)
- B \(\frac{L_2-L_1}{F_1+F_2}\)
- C \(\frac{F_1 L_2-F_2 L_1}{F_1-F_2}\)
- D \(\frac{F_1 L_1-F_2 L_2}{F_1-F_2}\)
Answer & Solution
Correct Answer
(C) \(\frac{F_1 L_2-F_2 L_1}{F_1-F_2}\)
Step-by-step Solution
Detailed explanation
Change in length of wire of length \(L\) is directly proportional to the external force applied \( \begin{array}{ll} & F_1 \propto\left(L_1-L\right) \\ \Rightarrow & F_1=K\left(L_1-L\right) \\ \text { Similarly, } & F_2=K\left(L_2-L\right) \end{array} \) Dividing Eq. (i) by Eq.…
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