TS EAMCET · Physics · Rotational Motion
A constant torque acting on a uniform circular wheel changes its angular momentum from \(\mathrm{A}_0\) to \(4 \mathrm{~A}_0\) in 4 seconds. The magnitude of the torque is
- A \(\frac{3 \mathrm{~A}_{\mathrm{o}}}{4}\)
- B \(\mathrm{A}_0\)
- C \(4 \mathrm{~A}_0\)
- D \(12 \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(\frac{3 \mathrm{~A}_{\mathrm{o}}}{4}\)
Step-by-step Solution
Detailed explanation
Torque \(\tau=\frac{\Delta \mathrm{L}}{\Delta \mathrm{t}}=\frac{4 \mathrm{~A}_0-\mathrm{A}_0}{4}=\frac{3}{4} \mathrm{~A}_0\)
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