TS EAMCET · Physics · Magnetic Effects of Current
Two particles carrying equal charges move parallel to each other with the speed \(150 \mathrm{~km} / \mathrm{s}\). If \(\mathbf{F}_1\) and \(\mathbf{F}_2\) are magnetic and electric forces between two charged particles then, \(\frac{\left|\mathbf{F}_1\right|}{\left|\mathbf{F}_2\right|}\) is \(\left(\right.\) Let \(\left.\mu_0 \varepsilon_0=\frac{1}{9 \times 10^{16}} \mathrm{~s}^2 / \mathrm{m}^2\right)\)
- A \(1.0 \times 10^{-6}\)
- B \(1.5 \times 10^{-7}\)
- C \(3.0 \times 10^{-6}\)
- D \(2.5 \times 10^{-7}\)
Answer & Solution
Correct Answer
(D) \(2.5 \times 10^{-7}\)
Step-by-step Solution
Detailed explanation
Given, two charge particles having same charge, \(q\) move with same speed i.e., \(v_1=v_2=150 \mathrm{~km} / \mathrm{s}=1.5 \times 10^5 \mathrm{~m} / \mathrm{s}\) Electric force between two moving charge particle is same as they are static, i.e.,…
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