TS EAMCET · Physics · Current Electricity
A battery of the emf \(18 \mathrm{~V}\) and internal resistance of \(3 \Omega\) and another battery of emf \(10 \mathrm{~V}\) and internal resistance of \(1 \Omega\) are connected as shown in figure. Then, the voltmeter reading is
- A \(10 \mathrm{~V}\)
- B \(12 \mathrm{~V}\)
- C \(16 \mathrm{~V}\)
- D \(8 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(12 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Net emf of the combination \( =18-10=8 \) Net resistance of the circuit \(=3+1=4\) Current in the circuit \(i=\frac{8}{4}=2 \mathrm{~A}\) \( \begin{aligned} \therefore \text { Potential difference }(V) & =E-i r=18-6 \\ & =12 \mathrm{~V} \end{aligned} \)
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