TS EAMCET · Physics · Rotational Motion
The temperature of a thin uniform circular disc, of one metre diameter is increased by \(10^{\circ} \mathrm{C}\). The percentage increase in moment of inertia of the disc about an axis passing through its centre and perpendicular to the circular face : (linear coefficient of expansion \(\left.=11 \times 10^{-6} /{ }^{\circ} \mathrm{C}\right)\)
- A 0.0055
- B 0.011
- C 0.022
- D 0.044
Answer & Solution
Correct Answer
(C) 0.022
Step-by-step Solution
Detailed explanation
Increase in area of disc \(\Delta A=A(2 \alpha) \Delta t\) \(=\pi(0.5)^2\left(2 \times 11 \times 10^{-6}\right) \times 10\) \(=0.000055 \pi\) New area of the disc, \(A^{\prime}=A+\Delta A\) \(\therefore \quad A^{\prime}=\pi(0.5)^2+0.000055 \pi\) or…
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