TS EAMCET · Physics · Mechanical Properties of Solids
In a tensile test on a metal bar of diameter \(0.015 \mathrm{~m}\) and length \(0.2 \mathrm{~m}\), the relation between the load and elongation within the proportional limit is found to be \(F=97.2 \times 10^6(\Delta L)\), where \(F\) is the load (in N) and \(\Delta L\) is the elongation (in \(\mathrm{m}\) ). The Young's modulus of the material in GPa is
- A 75.5
- B 85.6
- C 98.7
- D 110
Answer & Solution
Correct Answer
(D) 110
Step-by-step Solution
Detailed explanation
Given that, diameter of metal bar \((d)=0.015 \mathrm{~m}\) \[ \text { length } \begin{aligned} (L) & =0.2 \mathrm{~m} \\ F & =97.2 \times 10^6 \times \Delta L \end{aligned} \] We know that, \(Y=\frac{F L}{A \cdot \Delta L}\)…
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