TS EAMCET · Physics · Current Electricity
The relation between the current \(i\) (in ampere) in a conductor and the time \(t\) (in second) is \(i=12 t+9 t^2\). The charge passing through the conductor between the times \(t=2 \mathrm{~s}\) and \(t=10 \mathrm{~s}\) is
- A 3720 C
- B 3648 C
- C 3600 C
- D 3552 C
Answer & Solution
Correct Answer
(D) 3552 C
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {Current, } i=12 \mathrm{t}+9 \mathrm{t}^2, \mathrm{t}_1=2 \mathrm{~s}, \mathrm{t}_2=10 \mathrm{~s} \\ \therefore \quad & \text { Charge, } \mathrm{q}=\int_{\mathrm{t}_1}^{\mathrm{t}_2} \mathrm{idt}=\int_2^{10}\left(9 \mathrm{t}^2+12 \mathrm{t}\right)…
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