TS EAMCET · Physics · Motion In One Dimension
The deceleration of a car traveling on a straight highway is a function of its instantaneous velocity \(v\) given by \(\omega=a \sqrt{v}\), where \(a\) is a constant. If the initial velocity of the car is \(60 \mathrm{~km} / \mathrm{h}\), the distance of the car will travel and the time it takes before it stops are
- A \(\frac{2}{3} m_1 \frac{1}{2} s\)
- B \(\frac{3}{2 a} m, \frac{1}{2 a} s\)
- C \(\frac{3 a}{2} m, \frac{a}{2} s\)
- D \(\frac{2}{3 a} m, \frac{2}{a} s\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{3 a} m, \frac{2}{a} s\)
Step-by-step Solution
Detailed explanation
Deceleration \(\omega=-a \sqrt{v}\). But \(\quad \omega=\frac{d v}{d t} \quad \Rightarrow \frac{d v}{d t}=-a \sqrt{v}\)…
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