TS EAMCET · Physics · Current Electricity
The drift speed of electrons in a material is found to be \(0.3 \mathrm{~ms}^{-1}\) when an electric field of \(2 \mathrm{Vm}^{-1}\) is applied across it. The electron mobility (in \(\mathrm{m}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}\) ) in the material is
- A \(60 \times 10^{-2}\)
- B \(15 \times 10^{-2}\)
- C \(1350 \times 10^6\)
- D \(5400 \times 10^6\)
Answer & Solution
Correct Answer
(B) \(15 \times 10^{-2}\)
Step-by-step Solution
Detailed explanation
\(\mu = \frac{v_d}{E}\) \(\mu = \frac{0.3}{2}\) \(\mu = 0.15 \, \mathrm{m}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}\) \(\mu = 15 \times 10^{-2} \, \mathrm{m}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}\)
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