TS EAMCET · Physics · Rotational Motion
A circular disc of radius \(R\) and thickness \(\frac{R}{6}\) has moment of inertia \(I\) about an axis passing through its centre and perpendicular to its plane. It is melted and recasted into a solid sphere. The moment of inertia of the sphere about its diameter as axis of rotation is :
- A \(I\)
- B \(\frac{2 I}{3}\)
- C \(\frac{I}{5}\)
- D \(\frac{I}{10}\)
Answer & Solution
Correct Answer
(C) \(\frac{I}{5}\)
Step-by-step Solution
Detailed explanation
Moment of inertia of a disc, \(I=\frac{1}{2} M R^2\) Disc is melted and recasted into a solid sphere. \(\therefore\) Volume of sphere \(=\) Volume of disc \(\frac{4}{3} \pi R_1^3=\pi R^2 \times \frac{R}{6} \Rightarrow \frac{4}{3} R_1^3=\frac{R^3}{6}\)…
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