TS EAMCET · Physics · Oscillations
A point moves in the \(x y\)-plane according to the following equation, \(x=a \sin \omega t\), \(y=a(1-\cos \omega t)\), where \(a\) and \(\omega\) are positive constants. Find the angle between the point's velocity and acceleration vectors.
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{3}\)
- C \(\pi\)
- D \(2 \pi\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
Displacement vector, \(\begin{aligned} \mathbf{s} & =x(\hat{\mathbf{i}})+y(\hat{\mathbf{j}}) \\ & =a \sin (\omega t)(\hat{\mathbf{i}})+a[1-\cos (\omega t)](\hat{\mathbf{j}}) \end{aligned}\) Velocity vector,…
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