TS EAMCET · Physics · Current Electricity
A voltmeter of \(250 \mathrm{mV}\) range having a resistance of \(10 \Omega\) is converted into an ammeter of \(250 \mathrm{~mA}\) range. The value of necessary shunt is (nearly)
- A \(2 \Omega\)
- B \(0.1 \Omega\)
- C \(1 \Omega\)
- D \(10 \Omega\)
Answer & Solution
Correct Answer
(C) \(1 \Omega\)
Step-by-step Solution
Detailed explanation
A voltmeter of \(250 \mathrm{mV}\) range having resistance of \(10 \Omega\) \[ \begin{aligned} & \therefore & V_g & =G I_g \\ \Rightarrow & & 250 \times 10^{-3} & =10 \times I_g \\ \Rightarrow & & I_g & =25 \times 10^{-3} \mathrm{~A} \end{aligned} \] Shunt required to convert…
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