TS EAMCET · Physics · Thermodynamics
A reversible engine converts one-sixth of the heat supplied into work. When the temperature of the sink is reduced by \(62^{\circ} \mathrm{C}\), the efficiency of the engine is doubled. The temperatures of the source and sink are
- A \(99^{\circ} \mathrm{C}, 37^{\circ} \mathrm{C}\)
- B \(80^{\circ} \mathrm{C}, 37^{\circ} \mathrm{C}\)
- C \(95^{\circ} \mathrm{C}, 37^{\circ} \mathrm{C}\)
- D \(90^{\circ} \mathrm{C}, 37^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(99^{\circ} \mathrm{C}, 37^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
The efficiency of engine, \(\eta=\frac{T_1-T_2}{T_1}\) According to question, \(2 \eta=\frac{T_1-\left(T_2-62\right)}{T_1}\) or \(\quad \frac{1}{2}=\frac{T_1-T_2}{\left(T_1-T_2\right)+62}\) or \(62=\left(T_1-T_2\right)\) Only option (a) satisfies the condition.
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