TS EAMCET · Physics · Atomic Physics
The energy of an electron in the fourth excited state of the hydrogen atom is
- A \(-0.85 \mathrm{eV}\)
- B \(-1.70 \mathrm{eV}\)
- C 0
- D \(-0.544 \mathrm{eV}\)
Answer & Solution
Correct Answer
(D) \(-0.544 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{E}_{\mathrm{n}}=\frac{-13.6}{\mathrm{n}^2} \mathrm{eV} \\ & \Rightarrow \quad \mathrm{E}_5=\frac{-13.6}{5^2} \mathrm{eV} \\ & \Rightarrow \quad \mathrm{E}_5=-0.544 \mathrm{eV}\end{aligned}\)
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