TS EAMCET · Physics · Electrostatics
The flux of the electric field \(\overrightarrow{\mathrm{E}}=24 \hat{\mathrm{i}}+30 \hat{\mathrm{j}}+28 \hat{\mathrm{k}} \mathrm{NC}^{-1}\) through an area of \(20 \mathrm{~m}^2\) on the yz plane is
- A \(480 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- B \(600 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- C \(560 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- D \(1640 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Answer & Solution
Correct Answer
(A) \(480 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Step-by-step Solution
Detailed explanation
Electric field is given by \[ \overrightarrow{\mathrm{E}}=24 \hat{\mathrm{i}}+30 \hat{\mathrm{j}}+28 \hat{\mathrm{k}} \] Area, \(\vec{A}=20 \hat{i} \mathrm{~m}^2\) Electric flux, \(\overrightarrow{\mathrm{D}}=\overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{A}}\)…
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