TS EAMCET · Physics · Electromagnetic Waves
What is the amplitude of the electric field in a parallel beam of light intensity \(\left(\frac{15}{\pi}\right) \frac{\mathrm{W}}{\mathrm{m}^2}\) ? \(\left[\right.\) Assume,\(\left.\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \frac{\mathrm{Nm}^2}{\mathrm{C}^2}\right]\)
- A \(60 \mathrm{~N} / \mathrm{C}\)
- B \(50 \mathrm{~N} / \mathrm{C}\)
- C \(40 \mathrm{~N} / \mathrm{C}\)
- D \(30 \mathrm{~N} / \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(60 \mathrm{~N} / \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Intensity of parallel beam of light is given as \(I=\frac{1}{2} \varepsilon_0 E_0^2 c\)...(i) where, \(E_0=\) amplitude of electric field. Here,…
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