TS EAMCET · Physics · Gravitation
Find the acceleration of our galaxy, due to the nearest comparably sized galaxy. The approximate masses of each galaxy is \(8 \times 10^{11}\) solar mass and they are separated by 2 million light-years. Each galaxy has a diameter of 100000 light year. (Assume, 1 light year \(\approx 10^{16} \mathrm{~m}\), gravitational constant, \(G \approx 10^{-10}\left(\frac{\mathrm{Nm}^2}{\mathrm{~kg}^2}\right)\) and mass of sun \(=2.0 \times 10^{30} \mathrm{~kg}\) )
- A \(4 \times 10^{-13} \mathrm{~m} / \mathrm{s}^2\)
- B \(2 \times 10^{-13} \mathrm{~m} / \mathrm{s}^2\)
- C \(5 \times 10^{-15} \mathrm{~m} / \mathrm{s}^2\)
- D \(5 \times 10^{-13} \mathrm{~m} / \mathrm{s}^2\)
Answer & Solution
Correct Answer
(A) \(4 \times 10^{-13} \mathrm{~m} / \mathrm{s}^2\)
Step-by-step Solution
Detailed explanation
Here, masses of each galaxy are \(\begin{aligned} m_1 & =m_2=8 \times 10^{11} \text { solar mass } \\ & =8 \times 10^{11} \times 2 \times 10^{30} \mathrm{~kg} \\ & =16 \times 10^{41} \mathrm{~kg}\end{aligned}\) Distance between galaxies is…
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