TS EAMCET · Physics · Motion In Two Dimensions
A river \(200 \mathrm{~m}\) wide is flowing at a rate of \(3.0 \mathrm{~m} / \mathrm{s}\). A boat is sailing at a velocity of \(15 \mathrm{~m} / \mathrm{s}\) with respect to the water in a direction perpendicular to the river. How far from the point directly opposite to the starting point does the boat reach on the opposite bank?
- A \(25 \mathrm{~m}\)
- B \(60 \mathrm{~m}\)
- C \(40 \mathrm{~m}\)
- D \(50 \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(40 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
The given situation is shown in the following figure Velocity of river, \(v_r=3 \mathrm{~ms}^{-1}\) Velocity of boat, \(v_b=15 \mathrm{~ms}^{-1}\) Width of river \(=A B=200 \mathrm{~m}\) According to question, we have to calculate distance \(B C\). Time taken by boat to cross…
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