TS EAMCET · Physics · Thermal Properties of Matter
A steel pendulum clock manufactured at \(32^{\circ} \mathrm{C}\) and working at \(47^{\circ} \mathrm{C}\) is nearly (Coefficient of linear expansion of steel \(=12 \times 10^{-6} /{ }^{\circ} \mathrm{C}\) )
- A 7.8 s slow per day
- B 7.8 s fast per day
- C 15.6 s slow per day
- D 15.6 s fast per day
Answer & Solution
Correct Answer
(A) 7.8 s slow per day
Step-by-step Solution
Detailed explanation
\(\Delta T = 47^{\circ} \mathrm{C} - 32^{\circ} \mathrm{C} = 15^{\circ} \mathrm{C}\) \(\frac{\Delta T_p}{T_p} = \frac{1}{2} \alpha \Delta T = \frac{1}{2} (12 \times 10^{-6} /{ }^{\circ} \mathrm{C}) (15^{\circ} \mathrm{C}) = 90 \times 10^{-6}\)…
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