TS EAMCET · Physics · Ray Optics
A light ray travels from a medium with refractive index \(\mathrm{n}_1\) to another medium of refractive index \(\mathrm{n}_2\). If \(\mathrm{n}_1=2\) and \(\mathrm{n}_2=\sqrt{3}\), then find the critical angle.
- A \(15^{\circ}\)
- B \(30^{\circ}\)
- C \(45^{\circ}\)
- D \(60^{\circ}\)
Answer & Solution
Correct Answer
(D) \(60^{\circ}\)
Step-by-step Solution
Detailed explanation
Critical angle is defined by \[ \begin{aligned} & \sin \theta_{\mathrm{c}}=\frac{\mathrm{n}_2}{\mathrm{n}_1} \\ & \sin \theta_{\mathrm{c}}=\frac{\sqrt{3}}{2} \\ & \sin \theta_{\mathrm{c}}=\sin 60^{\circ} \\ & \theta_{\mathrm{c}}=60^{\circ} \end{aligned} \]
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