TS EAMCET · Physics · Thermal Properties of Matter
The temperature of a body is increased from \(T_1=127^{\circ} \mathrm{C}\) to \(T_2=227^{\circ} \mathrm{C}\). The ambient temperature is \(27^{\circ} \mathrm{C}\). The energies emitted per second by the body at \(T_1\) and \(T_2\) are \(E_1\) and \(E_2\) respectively. The ratio of \(\frac{E_2}{E_1}\) is
- A \(1.8\)
- B \(2.7\)
- C \(3.1\)
- D \(10.22\)
Answer & Solution
Correct Answer
(D) \(10.22\)
Step-by-step Solution
Detailed explanation
Given, temperature of body increases from \(T_1=127^{\circ} \mathrm{C}\) to \(T_2=227^{\circ} \mathrm{C}\) and ambient temperature, \(T_0=27^{\circ} \mathrm{C}\) By Stefan-Boltzman's law, energy emitted per second is given by i.c., \(E=\varepsilon \sigma\left(T^4-T_0^4\right)\)…
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