TS EAMCET · Physics · Center of Mass Momentum and Collision
A circular hole of radius \(3 \mathrm{~cm}\) is cut out from a uniform circular disc of radius \(6 \mathrm{~cm}\). The centre of the hole is at \(3 \mathrm{~cm}\), from the centre of the original disc. The distance of centre of gravity of the resulting flat body from the centre of the original disc is
- A 0.5 cm
- B 1 cm
- C 1.5 cm
- D 0.75 cm
Answer & Solution
Correct Answer
(B) 1 cm
Step-by-step Solution
Detailed explanation
Let mass per unit area of the disc \(=m\) Total mass of disc, \(M=\pi R^2 m\) Mass of the scooped out portion of the disc, \(M^{\prime}=\pi r^2 m\) For small objects, centre of gravity and centre of mass are at same position. We take the centre \(O\) of the disc as the origin.…
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