TS EAMCET · Physics · Semiconductors
In an \(n-p-n\) transistor, \(95 \%\) of emitted electrons reach the collector. If the base current is \(2 \mathrm{~mA}\), then collector current is
- A 19 mA
- B 38 mA
- C 9.5 mA
- D 48 mA
Answer & Solution
Correct Answer
(B) 38 mA
Step-by-step Solution
Detailed explanation
Given, base current in \(n-p-n\) transistor, \(I_B=2 \mathrm{~mA}=2 \times 10^{-3} \mathrm{~A}\) Since, \(95 \%\) of emitted electrons reach the collector, hence Collector current, \(I_C=95 \%\) of \(I_E \Rightarrow I_C=0.95 I_E \Rightarrow I_E=\frac{I_C}{0.95}\)...(i) But we…
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