TS EAMCET · Physics · Magnetic Effects of Current
A short bar magnet placed with its axis at \(30^{\circ}\) with an external field of \(800 \mathrm{G}\) experiences a torque of \(0.016 \mathrm{Nm}\). The magnetic moment of the bar magnet is
- A \(0.4 \mathrm{Am}^2\)
- B \(0.5 \mathrm{Am}^2\)
- C \(0.6 \mathrm{Am}^2\)
- D \(0.7 \mathrm{Am}^2\)
Answer & Solution
Correct Answer
(A) \(0.4 \mathrm{Am}^2\)
Step-by-step Solution
Detailed explanation
\(\because \tau=M B \sin \theta\) where, \(\tau=\) torque experienced by bar magnet \(=0.016 \mathrm{~N}-\mathrm{m}\) \(M=\) magnetic moment of bar magnet \(B=\) external magnetic field intensity \(=800 \mathrm{G}=800 \times 10^{-4} \mathrm{~T}=8 \times 10^{-2} \mathrm{~T}\)…
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