TS EAMCET · Physics · Ray Optics
An object of height 3.6 cm is placed normally on the principal axis of a concave mirror of radius of curvature 30 cm. If the object is at a distance of 10 cm from the principal focus of the mirror, then the height of the real image formed due to the mirror is
- A 5.4 cm
- B 3.6 cm
- C 1.8 cm
- D 2.7 cm
Answer & Solution
Correct Answer
(A) 5.4 cm
Step-by-step Solution
Detailed explanation
\( f = \frac{30}{2} = 15 \) cm \( u = f + 10 = 15 + 10 = 25 \) cm \( \frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{15} - \frac{1}{25} = \frac{5-3}{75} = \frac{2}{75} \Rightarrow v = 37.5 \) cm \( h_i = h_o \times \frac{v}{u} = 3.6 \times \frac{37.5}{25} \)…
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