TS EAMCET · Physics · Capacitance
In the following figure \(C_1=5 \mu \mathrm{F}\), \(C_2=C_3=10 \mu \mathrm{F}\) and \(\varepsilon=20 \mathrm{~V}\). Initially the switch \(S\) is connected to point \(A\) until capacitor \(C_1\) is fully charged. Afterwards switch is thrown to left side and connected to point \(B\). The charge on capacitor \(C_3\) after equilibrium is reached will be

- A \(40 \mu \mathrm{C}\)
- B \(100 \mu \mathrm{C}\)
- C \(50 \mu \mathrm{C}\)
- D \(20 \mu \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(40 \mu \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given that, \(C_1=5 \mu \mathrm{F}, C_2=C_3=10 \mu \mathrm{F}\) and \(E=20 \mathrm{~V}\) When the switch is connected to point \(A\). Then, situation of the circuit is shown below. Charge stored in \(C_1\), \( Q=C_1 V_1=C_1 E=5 \times 20 \mu \mathrm{C}=100 \mu \mathrm{C} \) When…
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