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TS EAMCET · Physics · Wave Optics

In an experiment, light passing through two slits separated by a distance of \(0.3 \mathrm{~mm}\) is projected on to a screen placed at \(1 \mathrm{~m}\) from the plane of slits. It is observed that the distance between the central fringe and the adjacent bright fringe is \(1.9 \mathrm{~mm}\). The wavelength of light in \(\mathrm{nm}\) is

  1. A 450
  2. B 495
  3. C 530
  4. D 570
Verified Solution

Answer & Solution

Correct Answer

(D) 570

Step-by-step Solution

Detailed explanation

Distance between central height fringe and next bright fringe is width of one dark fringe \(\beta\). So, \[ \beta=\frac{\lambda D}{d} \] \[ \Rightarrow \quad 1.9 \times 10^{-3}=\frac{\lambda \times 1}{0.3 \times 10^{-3}} \]…
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