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TS EAMCET · Physics · Kinetic Theory of Gases

A molecule is travelling in air at \(300 \mathrm{~K}\) and \(1 \mathrm{~atm}\), and the radius of the molecule is \(0.6 \times 10^{-10} \mathrm{~m}\). Calculate the approx. mean free path of the molecule. (The number density is \(2.44 \times 10^{25}\) molecules \(/ \mathrm{m}^3\) )

  1. A \(\frac{0.2}{\pi} \times 10^{-5} \mathrm{~m}\)
  2. B \(\frac{0.3}{\pi} \times 10^{-5} \mathrm{~m}\)
  3. C \(\frac{0.4}{\pi} \times 10^{-5} \mathrm{~m}\)
  4. D \(\frac{0.1}{\pi} \times 10^{-5} \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{0.2}{\pi} \times 10^{-5} \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

Given that, temperature, \(T=300 \mathrm{~K}\) Pressure, \(p=1\) atm \(=1.01 \times 10^5 \mathrm{~N} / \mathrm{m}^2\) Radius, \(r=0.6 \times 10^{-10} \mathrm{~m}\), diameter \(d=1.2 \times 10^{-10} \mathrm{~m}\) Number density, \(\rho=2.44 \times 10^{25}\) molecules…
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