TS EAMCET · Physics · Oscillations
A pendulum has a time period \(\mathrm{T}\) in air. When it is made to oscillate in water its time period is \(\sqrt{2} \mathrm{~T}\). Then the relative density of the material of the bob of the pendulum is (neglect damping)
- A \(\sqrt{2}\)
- B \(2\)
- C \(2 \sqrt{2}\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
The effective acceleration of a bob in water \[ g^{\prime}=g\left(1-\frac{\sigma}{\rho}\right) \] Here \(\sigma\) and \(\rho\) are the density of water and the bob respectively. The time period in air is \[ T=2 \pi \sqrt{\frac{I}{g}} \] The time period in water is…
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