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TS EAMCET · Physics · Rotational Motion

A rod of length \(l\) is held vertically stationary with its lower end located at a point \(P\), on the horizontal plane. When the rod is released to topple about \(P\), the velocity of the upper end of the rod with which it hits the ground is

  1. A \(\sqrt{\frac{g}{l}}\)
  2. B \(\sqrt{3 g l}\)
  3. C \(3 \sqrt{\frac{g}{l}}\)
  4. D \(\sqrt{\frac{3 g}{l}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{3 g l}\)

Step-by-step Solution

Detailed explanation

In this process potential energy of the metre stick will be converted into rotational kinetic energy. PE of metre stick \(=\frac{m g l}{2}\) Because its centre of gravity lies at the middle of the rod. Rotational kinetic energy \(E=\frac{1}{2} I \omega^2\) \(I=\) moment of…