TS EAMCET · Physics · Center of Mass Momentum and Collision
Four identical particles each of mass ' \(m\) ' are kept at the four comers of a square of side ' \(a\) '. If one of the particles is removed, the shift in the position of the centre of mass is
- A \(\sqrt{2} a\)
- B \(\frac{3 a}{\sqrt{2}}\)
- C \(\frac{a}{\sqrt{2}}\)
- D \(\frac{a}{3 \sqrt{2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{a}{3 \sqrt{2}}\)
Step-by-step Solution
Detailed explanation
From figure (i) \& (ii) of mass at point C is removed the there shift in the position of the centre of mass is \(\frac{1}{3} \frac{a}{\sqrt{2}}\)
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