TS EAMCET · Physics · Kinetic Theory of Gases
A thin hollow sphere of mass \(m\) is completely filled with a liquid of mass \(m\). When the sphere rolls with a velocity \(v\), kinetic energy of the system is (neglect friction)
- A \(\frac{1}{2} m v^2\)
- B \(m v^2\)
- C \(\frac{4}{3} m v^2\)
- D \(\frac{4}{5} m v^2\)
Answer & Solution
Correct Answer
(C) \(\frac{4}{3} m v^2\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text { Total energy } & =\mathrm{KE}+\text { rotational } \mathrm{KE} \\ & =\frac{1}{2}(2 m) v^2+\frac{1}{3} m v^2 \\ & =\frac{4}{3} m v^2\end{aligned}\)
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