TS EAMCET · Physics · Capacitance
Four identical metal plates are located in air at equal distance \(d\) from each other. The area of each plate is \(S\). If the outer most plates are connected by a conducting wire as shown in the figure the capacitance between points \(A\) and \(B\) will be
- A \(\frac{\varepsilon_0 S}{d}\)
- B \(\frac{3}{2} \frac{\varepsilon_0 S}{d}\)
- C \(\frac{1}{2} \frac{\varepsilon_0 S}{d}\)
- D \(\frac{2}{3} \frac{\varepsilon_0 S}{d}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{2} \frac{\varepsilon_0 S}{d}\)
Step-by-step Solution
Detailed explanation
The equivalent arrangement of given combination is shown in the following figure, we know that the capacitance, \(C=\frac{\varepsilon_0 S}{d}\) where, \(S\) is the area of each plate and \(d\) is distance between two plates. So, equivalent capacitance between points \(A\) and…
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