TS EAMCET · Physics · Center of Mass Momentum and Collision
A particle of mass \(m_1\) moving along the \(X\)-axis collides with a stationary particle of mass \(m_2\) and deviates by an angle \(30^{\circ}\) to the \(X\)-axis as shown in the figure. If the percentage change in kinetic energy of the combined system of these two particles reduces by \(50 \%\), then the ratio of the masses \(\frac{m_2}{m_1}\) is
- A 8
- B 6
- C \(\frac{8}{7}\)
- D \(\frac{1}{6}\)
Answer & Solution
Correct Answer
(A) 8
Step-by-step Solution
Detailed explanation
Momentum is conserved in both \(x\) and \(y\) directions separately \( \begin{array}{ll} \Rightarrow & m_1 u=m_2 v_2 \cos 30^{\circ} \\ \text { and } & m_1 v_1=m_2 v_2 \sin 30^{\circ} \end{array} \) Also, loss of K E \(=50 \%\)…
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